13x^2+24x+11=0

Solution for 13x^2+24x+11=0 equation:

13x^2+24x+11=0

a = 13; b = 24; c = +11;
Δ = b2-4ac
Δ = 242-4·13·11
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-2}{2*13}=\frac{-26}{26}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+2}{2*13}=\frac{-22}{26}
=-11/13
$